Comments for RC Model Video Clips

Comment on how can i make my rc helicopter better for free? by Ah Boi

Ah Boi — Sun, 20 May 2012 15:42:12 +0000

I am afraid that there is no way that you can make your rc heli better for free.
To make it better you definitely need to spend lots of money to ‘bling’ it with metal parts, carbon fiber blades, new gyro, digital servos, new transmitter and stuff. Even with these upgraded, intermediate to advanced skill is required to be able to fly 3D/aggressive stunts.

Hope it helps.

http://www.rcuniverse.com/

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Comment on Receiver pack for Super vee 27 brushless rc boat? by AN-DY

AN-DY — Sun, 20 May 2012 12:43:07 +0000

The Supervee 27 already has a receiver pack:
http://www.aquacraftmodels.com/boats/aqub17-supervee-27/aqub17xxai09s-b.jpg
On the photo its the unit labelled RX-100 – just make sure your 7 cell battery is arranged so that it does not impede the hatch from closing up when installed.

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Comment on Duratrax Street Force GP2? by khaosofstorms

khaosofstorms — Sun, 20 May 2012 09:42:09 +0000

ok iv been into rc gas planes and cars for about a year now and it sounds like you dint brake that engine in right maybe but the best be is look at this site the best rc site there is for questions.

http://www.rcuniverse.com

the r/c freaks hang out when there not playing with there toys or charging batterys.

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Comment on Rocket Launch question!!!? by Steve

Steve — Sun, 20 May 2012 08:42:30 +0000

Velocity while burning = Vb = Vo + √(2ay) = 40 + √(2*1*170) = 58.439 m/s. The height during burning, Yb = 170 = 40Tb + ½aTb². This can be solved for Tb = 4.04543 sec

b) Velocity after burning = Va = Vb – gT. Letting this be 0→T for max height; T1 = Vb/g = 5.963 sec. So, the time to Hmax is Tb + T1 = 10.0085 sec

a) Hmax = 170 + Vb*T1 – ½gT1² = 344.24 m

c) Time to fall from this height = Tf = √(2(Hmax)/g) = 8.3817 sec, so the total time in flight is Tb + T1 + Tf = 18.3902 sec

Both the answerers above made the same mistake. They wrote:

v^2 = u^2 + 2as

It should be v² = u² + 2u√(2as) + 2as. (See my 1st eq above)

My best guess

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Comment on Rocket Launch question!!!? by SOMEBODY

SOMEBODY — Sun, 20 May 2012 07:43:02 +0000

first, find the veloicity of the rocket at 170m.

Vf^2 = 2ad + Vi^2
Vf^2 = 2(1)(170) + (40)^2
Vf^2 = 1940
Vf = 44.045 m/s

When the engine stops at 170m, the rock is already traveling at 44.045m/s and accleration is -9.8m/s^2. Find the distance it goes. When it reaches its maximun height, its final velocity is 0m/s

Vf^2 = 2ad + Vi^2
0^2 = 2(-9.8)d + (44.045)^2
-1939.962 = -19.6d
d = 98.978m

the maxium height is 170m + 98.978m = 268.978m.

b) find the time it takes the rock to reach 170m

Vf = at + Vi
44.045 = = 1t + 40
t = 4.045s

find the time it takes from 170m to its maximun height
Vf = at + Vi
0 = -9.8t + 44.045
-44.045 = -9.8t
t = 4.494s

so the total time is 4.045 + 4.494 = 8.539s

c) First off, fine the speed when the rocket hits the ground.
Vf^2 = 2ad + Vi^2
Vf^2 = 2(-9.8)(-268.978)
Vf = -72.608 m/s

find the time
Vf = at + Vi
-72.608 = (-9.8)t + 0
t = 7.409s

the time total time is 8.539 + 7.409 = 15.948s

Live free or die……otherwise you are left to exist as a trembling coward, disguised as a liberal Democrat.

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Comment on Name of this fabric? 10points best answer!!? by pattiann42

pattiann42 — Sun, 20 May 2012 06:42:57 +0000

Tone the body or wear a body shaper.

The actual fabric is not available as it was made especially for the desginer.

Banana Hobby

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Comment on Rocket Launch question!!!? by Dr D

Dr D — Sun, 20 May 2012 06:42:57 +0000

Phase 1: Engine on
a = 1
u = 40
s = 170
s = ut + 1/2 at^2
170 = 40t + 0.5t^2
You can solve t = 4.05 sec

v^2 = u^2 + 2as
= 40^2 + 2*1*170
v = 44.05 m/s

Phase 2. Engine off to maximum height.
Change in KE = 1/2 * m * (44.05)^2
Change in PE = mgh
h = 44.05^2 / (2g) = 98.8 m

Add this to 170 to get max height = 268.8 m

At max height, v = 0
so 0 = 44.05 – 9.81t
t = 4.49 sec
After lift off this is 4.49 + 4.05 = 8.54 sec

Phase 3: Free fall to ground
u = 0
s = 268.9
268.9 = 0 + g/2 * t^2
t = 7.4 sec

Total time in air = 7.4 + 8.54 = 15.94 sec

Live free or die……otherwise you are left to exist as a trembling coward, disguised as a liberal Democrat.

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Comment on Name of this fabric? 10points best answer!!? by Stargazer

Stargazer — Sun, 20 May 2012 05:42:38 +0000

The designer is Pierre Balmain — the material is a double knit. It will not hold in excess anything — the lady in the dress has a phenomenal body — the rest of us need to wear full body shapers.

Banana Hobby

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Comment on Name of this fabric? 10points best answer!!? by Noreb

Noreb — Sun, 20 May 2012 04:42:02 +0000

Crepe

Banana Hobby

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Comment on What Types of Engines Were Previously Used in Newfoundland Trains? by rdenig_male

rdenig_male — Sun, 20 May 2012 02:42:20 +0000

They appear to have used initially steam locomotives and latterly some diesels. The wiki link gives a good history, the second site has some photographs. A search gave over 300,000 replies, so there may well be some sites with more details and photos.

http://en.wikipedia.org/wiki/Newfoundland_Railway
http://www.durham.net/~kburt/NewfoundlandTrains.html

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